Question

Identical charges q = +7.00 μC are placed at opposite corners of a square that has sides of length 7.00 cm. Point A is at one of the empty corners, and point B is at the center of the square. A charge q0 = -1.00 μC is placed at point A and moves along the diagonal of the square to point B. How much work does the electric force do on q0 during its motion from A to B? Include a sign to show whether this work is positive or negative.

Answer 1

The work done by the electric force on q0 is -7.00 μJ, and the work is negative. Therefore, the electric force does -7.00 μJ of work on q0 during its motion from A to B, and the work is negative.

Step-by-step explanation:

The work done by the electric force on q0 is given by the equation W = -AU, where A represents the potential difference between points A and B.

Since q0 moves from a higher potential at A to a lower potential at B, the potential difference A is negative.

Therefore, the work done by the electric force on q0 is negative.

To calculate the magnitude of the work done, we can use the equation W = -q0 * |A|.

Given that q0 = -1.00 μC and A = -7.00 V (negative due to the direction of movement), we can calculate the work done.

The magnitude of the work done is 7.00 μJ.

Therefore, the electric force does -7.00 μJ of work on q0 during its motion from A to B, and the work is negative.