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A 100 N force is applied at an angle of 30° to the horizontal to move a 15 kg object at a constant speed for a horizontal distence of 5m

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Answer: Your Welcome!

Step-by-step explanation:

The work done by the force is given by the equation:

Work = Force x Distance x cos (Theta)

where Theta is the angle between the force and the direction in which the work is being done.

In this case, the work done by the force is:

Work = 100 N x 5 m x cos (30°)

Work = 433.01 J

The work done by the force is equal to the change in kinetic energy of the object, so the kinetic energy gained by the object is 433.01 J.

The kinetic energy gained by the object is given by the equation:

KE = 1/2 mv^2

where m is the mass of the object and v is the velocity of the object.

Therefore, the velocity of the object is given by:

v = sqrt (2KE/m)

v = sqrt (2 x 433.01 J / 15 kg)

v = 5.22 m/s

User Cem U
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