Answer:
Step-by-step explanation:
To solve this problem, we can use the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
At STP (standard temperature and pressure), the temperature is 0°C or 273.15 K, and the pressure is 1 atm or 101.325 kPa.
We can use the ideal gas law to find the number of moles of chlorine gas in the sample:
n = PV/RT
where P is the pressure, V is the volume, R is the gas constant, and T is the temperature in Kelvin.
First, we need to convert the given temperature of 25.2°C to Kelvin:
T = 25.2°C + 273.15 = 298.35 K
Now we can calculate the number of moles of chlorine gas in the sample:
n = (100.8 kPa)(353.2 mL)/(8.314 J/K/mol)(298.35 K)
n = 0.0158 mol
Next, we can use the number of moles and the ideal gas law to find the volume at STP:
V = nRT/P
V = (0.0158 mol)(8.314 J/K/mol)(273.15 K)/(101.325 kPa)
V = 0.364 L or 364 mL
Therefore, the volume of the chlorine gas at STP would be 364 mL.