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What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO.)?

User RaZik
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1 Answer

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6.023\text{ x 10}^(23)\text{ molecules are present in 1 mole of CuSO}_4\text{ i.e. 159.5 g of CuSO}_4

So, using unitary method


3.36\text{ x 10}^(23)\text{ molecules will be there in }\frac{159.5}{6.023\text{ x 10}^(23)}\text{ x 3.36 x10}_{\placeholder{⬚}^{\placeholder{⬚}}}^(23)
=\text{ 88.97 g of CuSO}_4

User JamesDullaghan
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