Question

Write an equation of the line with slope 2/3 that goes through the point (-2,5) (if possible can you also write an equation of a line that passes through (-1,2) and is parallel to a line with x-intercept (0,1), please and thank you!)

Answer 1

y = 2/3x + 19/3

Explanation:

Use the slope-intercept formula y = mx + b where m=slope and b=y-intercept.

Use the point (-2, 5) to substitute for (x, y) and slope(m) = 2/3

y = mx + b will now be

5 = (2/3)(-2) + b

Simplify

5 = -4/3 + b

Solve for b

5 + 4/3 = b or 15/3 + 4/3 = b ; therefore, b = 19/3

You know your slope(m) = 2/3 and your y-intercept(b) = 19/3 plug it back into the slope-intercept form.

y = 2/3x + 19/3