Answer: 5a. 0% 5b. 50% 5c. 50%
Explanation: It is asking for you to cross an individual who is heterozygous for this trait, Ee, with someone who has attached earlobes. Because this is the recessive trait they must be ee. With that in mind your Punnett Square should be an Ee x ee. So 0% of the offspring will be homozygous dominant, EE. 50% will be homozygous recessive, ee. And 50% will be heterozygous, Ee.
Hope this helps.