219k views
0 votes
If (x-1) is a factor of (x^3-3x^2+5x+n), what is the value of n?

User Cc Young
by
7.6k points

1 Answer

3 votes

Answer:

n = - 3

Explanation:

if (x - a) is a factor of a polynomial f(x) , then the remainder on division by (x - a) is zero and f(a) = 0

given (x - 1) is a factor of the polynomial , then substitute x = 1 and equate to zero, that is

(1)³ - 3(1)² + 5(1) + n = 0

1 - 3(1) + 5 + n = 0

1 - 3 + 5 + n = 0

3 + n = 0 ( subtract 3 from both sides )

n = - 3

User Rerun
by
7.9k points