Answer:
Given equation are 3x+4y=11 and 2x+3y=8
Comparing with a
1
x+b
1
y+c
1
=0 and a
2
x+b
2
y+c
2
=0 we have
a
1
=3,b
1
=4,c
1
=−11 and a
2
=2,b
2
=3,c
2
−8
Now , x=
a
1
b
2
−a
2
b
1
b
1
c
2
−b
2
c
1
and y=
a
1
b
2
−a
2
b
1
c
1
a
2
−c
2
a
1
⇒x=
3×3−2×4
4x(−8)−3×(−11)
and y=
3×3−2×4
−11×2−(−8)×3
⇒x=
9−8
−32+33
and y=
9−8
−22+24
⇒x=1 and y=2