Question

Answer the following questions. will give alot of points

1.The angle of depression from an airplane to the top of an air traffic control tower is 56°. If the tower is 320 feet tall and the the airplane is flying at an altitude of 7,450 feet, how far away is the airplane from the control tower? Round to the nearest tenth.





2.the town park does an outdoor movie night every Saturday during the summer on a large screen. Kate is sitting 36 feet from the base of the screen, watching a movie with her family. If the angle of elevation from Kate to the top of the screen is 24°, how tall is the movie screen? Round to the nearest tenth.

Answer 1

Answer:1273.8

Explanation:

because i used p m it really works great

Answer 2

The distance between the airplane and the control tower can be found using the tangent ratio

Explanation:

1.The distance between the airplane and the control tower can be found using the tangent ratio:

distance = (tangent of 56°)*(the difference in altitude between the plane and the tower)

distance = (tangent of 56°)*(7450 - 320)

distance = (1.45)*(7,130)

distance = 10,389.5 feet

Rounded to the nearest tenth, the distance between the plane and the tower is 10,389.6 feet.

2.The height of the movie screen can be found using the tangent ratio:

height = (tangent of 24°)*(distance from the base of the screen to Kate)

height = (tangent of 24°)*(36)

height = (0.4226)*(36)

height = 15.21 feet

Rounded to the nearest tenth, the height of the movie screen is 15.2 feet.