Answer:
51.84%.
t(24) = 2.08, p < .05, d = 2.00.
Step-by-step explanation:
The correlation coefficient between spousal relationship quality and cardiovascular risk is -0.72.
The negative sign indicates an inverse relationship between the two variables.
The absolute value of the correlation coefficient indicates a strong relationship between the two variables.
To calculate the percent of variance accounted for by spousal relationship quality:
Square the correlation coefficient to get the coefficient of determination: 0.72^2 = 0.5184.
Multiply by 100 to get the percent: 0.5184 x 100 = 51.84%.
Based on these results, it can be said that there is a strong negative relationship between spousal relationship quality and cardiovascular risk. However, correlation does not necessarily imply causation, so it cannot be definitively stated that spousal relationship quality influences cardiovascular risk.
To compute the effect size:
Calculate Cohen's d: d = (mean1 - mean2) / estimated standard deviation = (4.68 - 2.68) / 1.00 = 2.00.
Determine the magnitude of the effect size using Cohen's criteria: a d of 2.00 is considered a large effect size.
The full results of the t-test analysis are:
t(24) = 2.08, p < .05, d = 2.00.
This indicates that the difference between the two groups is statistically significant and has a large effect size.