Question

Kirill purchased 20 cows, pigs and chickens for $3,447. If cows cost $750 each, pigs cost $60 each, and chickens cost $3 each, and he bought two more chickens than

pigs, how many of each animal did he buy?

Answer 1

The answer is 32














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Answer 2

Let's use variables to represent the number of cows, pigs, and chickens that Kirill bought.

Let's use c for the number of cows, p for the number of pigs, and h for the number of chickens.

From the problem, we know that:

c + p + h = 20 (he bought 20 animals in total)
750c + 60p + 3h = 3447 (the total cost of the animals)

We also know that he bought two more chickens than pigs, so:

h = p + 2

Now we can use these three equations to solve for c, p, and h. One way to do this is to use substitution. Solving one of the equations for one of the variables and then substituting that expression into the other equations, we get:

p = h - 2 (from the relationship between h and p)

c + (h - 2) + h = 20 (substituting into the first equation)

c + 2h = 22

c = 22 - 2h (solving for c)

Substituting the expressions for c and p into the second equation, we get:

750(22 - 2h) + 60(h - 2) + 3h = 3447

16500 - 1500h + 60h - 120 + 3h = 3447

-1437h = -13083

h = 9

Now we can use the expressions for h and p to find c:

c + (9 - 2) + 9 = 20

c = 4

Therefore, Kirill bought 4 cows, 7 pigs, and 9 chickens.