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A stunt person opens his parachute at a height of 505 feet above the ground. He then descends at a constant rate.

Let y represent his height above the ground in feet. Let x represent the time, in seconds, he spent descending with his parachute open. Which equation is represented by the graph?

Question 2 options:

y = 505x + 17


y = 17x + 505


y = –17x + 505


y = 17x – 505

A stunt person opens his parachute at a height of 505 feet above the ground. He then-example-1
User Walter K
by
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2 Answers

3 votes

Answer:

17x + 505

y=MX+b

Solve it by using a linear equation, the graph is going down the slope must be negative

-17 slope is The Right answer for you.

User GDB
by
8.4k points
5 votes

Answer:

It's -17x + 505

Explanation:

The linear equation is like y=mx+b

Solve it by using linear equation knowledge: because the graph is going down, or the height is descending, so the the slope must be negative.

And the choise of slope is 505, 17, -17, 17, so the one with negative: -17 slope is correct.

User Manuel Aldana
by
8.5k points
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