Question

An electron moving through an electric field of 400 N/C and a magnetic field of .15 T experiences no net force. The two fields and the direction if motion are all mutually perpendicular. Calculate the speed of the electron.

Answer 1

Step-by-step explanation:

The force on an electron moving through an electric field is given by:

F = qE

where q is the charge of the electron, and E is the electric field.

The force on an electron moving through a magnetic field is given by:

F = qvB

where v is the speed of the electron, and B is the magnetic field.

Since the electron is experiencing no net force, the electric force must be balanced by the magnetic force. Thus:

qE = qvB

Solving for v, we get:

v = E/B

Substituting the given values, we get:

v = 400 N/C / 0.15 T

v = 2666.67 m/s

Therefore, the speed of the electron is 2666.67 m/s.