Question

Solve for X:


`16^x + 2^3^x^+^1-2^2^x^+^3=0`

I know that the
`16^x` can be written as
`2^4^x` to keep it consistent with the rest of the problem, but I keep getting multiple different answers despite being told X = 1. Any help to learn how to solve this would be appreciated!

Answer 1

Split into three equations

2^2x=0; 2^x=0; 2^x+4=0


Add 2 to both sides

2^x=2^1 ; 2^x+4=0


Equate exponent of 2 on both sides

X=1; 2^x=-4


Subtract 4 from both sides


Solution

X=1