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1. How many electrons pass through a filament of a light bulb in 2.00 s if the charge passing through the filament is 1.67 C

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Answer: Approximately 1.04 x 10^19 electrons pass through the filament of the light bulb in 2.00 seconds.

Step-by-step explanation:

To calculate the number of electrons passing through a filament of a light bulb in 2.00 seconds, we can use the fact that the total charge passing through the filament is given as 1.67 C and the charge on a single electron is -1.6 x 10^-19 C.

The number of electrons passing through the filament is given by:

number of electrons = total charge / charge on a single electron

Substituting the given values, we get:

number of electrons = 1.67 C / (-1.6 x 10^-19 C)

Using a calculator, we get:

number of electrons = 1.04 x 10^19 electrons

Therefore, approximately 1.04 x 10^19 electrons pass through the filament of the light bulb in 2.00 seconds.

User Pieter Hamman
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