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What is the rule for the following geometric sequence? 64,-32,16,-8

an = 64(1/2)^n-1

an= 64(2)^n-1

an= 64(-2)^n-1

an= 64(- 1/2)^n-1

User Jtimperley
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Answer: To find the rule for a geometric sequence, we need to determine the first term (a1) and the common ratio (r).

The given sequence is 64, -32, 16, -8. We can see that the first term is 64, and to get to the second term, we need to multiply the first term by -1/2. To get to the third term, we need to multiply the second term by -1/2, and so on.

So, the common ratio (r) is -1/2, since each term is obtained by multiplying the preceding term by -1/2.

The formula for the nth term (an) of a geometric sequence with first term a1 and common ratio r is:

an = a1 * r^(n-1)

Substituting the values we found, we get:

an = 64 * (-1/2)^(n-1)

Therefore, the rule for the given geometric sequence is:

an = 64 * (-1/2)^(n-1)

Explanation:

User Anuj Pandey
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