Answer:
the combined train cars will be moving east at a speed of 1 m/s after the perfectly inelastic collision.
Step-by-step explanation:
First, we can calculate the initial momentum of the first train car before the collision:
p1 = m1v1 = 1650 kg * 2 m/s = 3300 kgm/s east
Since the second train car is stationary, its initial momentum is zero:
p2 = m2*v2 = 0
The total momentum before the collision is therefore:
p_total = p1 + p2 = 3300 kg*m/s east
After the collision, the two train cars stick together and move as one, so we can treat them as a single object with a combined mass of 2*m1 = 3300 kg. Let's call the final velocity of the combined train cars v_final.
The conservation of momentum tells us that the total momentum after the collision is also p_total, so we can write:
p_total = m_total * v_final
Substituting in the values we have:
3300 kg*m/s east = 3300 kg * v_final
Solving for v_final, we get:
v_final = 1 m/s east
So the combined train cars will be moving east at a speed of 1 m/s after the perfectly inelastic collision.