Question

What's the possible values of z when t = 81

( be it real or complex number )


`{z}^(2) = √(t)`
​​
So annoying ~

Answer 1

• 
  `\boxed{\mathrm{z=\pm 3}}`

Explanation:

`\mathrm{z^2=√(t), \; when, \; t=81}`

Substitute t with 81:-

`\mathrm{z^2=√(81)}`

Since 9*9 =81, square of 81 is 9:-

`\mathrm{z^2=9}`

Take the square root of both sides.

`\mathrm{z=\pm √(9) }`

and since 3*3 = 9 the square root of 9 will be 3.:-

`\mathrm{z=\pm 3}`

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Hope this helps!