Question

A fixed quantity of gas at a constant temperature has an initial volume of 4.0 L and an initial pressure of 8 atm. If I decrease the volume of the gas and keep the temperature and amount constant, what happens to the pressure?

A. Increases
B. Decrease
C. Stays the same

A fixed quantity of gas at a constant pressure occupies a volume of 5.00 L at a temperature of 150.0K. Use Charles law to calculate what temperature the gas will be if the volume is increased to 10 L (V1/T1 = V2/T2).
A. 75 K
B. 0.333K
C. 3 K
D. 300 K

A fixed quantity of gas at a constant temperature exhibits a pressure of 6 atm and occupies a volume of 10.7 L. Use Boyle’s law to calculate the volume the gas will occupy if the pressure is increased to 12 atm. (P1V1=P2V2)
A. 5.35 L
B. 6.73 L
C. 27.4 L
D. 21.4 L

A fixed quantity of gas at a constant temperature exhibits a pressure of 8 atm and occupies a volume of 13.2 L, its pressure is then increased to 12 atm.
What equation would be used for this problem?
A. P1/V1 = P2/V2
B. P1/T1=P2/T2
C. V1/T1 = V2/T2
D. P1V1=P2V2

A fixed quantity of gas at a constant temperature exhibits a pressure of 6 atm and occupies a volume of 10.7 L. Use Boyle’s law to calculate the pressure the gas will occupy if the volume is increased to 15 L. (P1V1=P2V2)
A. 4.28 atm
B. 26.75 atm
C. 8.4 atm
D. 963 atm

A fixed quantity of gas has an initial volume of 2.0L, a pressure of 3.0 atm, and a temperature of 250K. If the pressure is changed to 5.0 atm and the volume is chaged to 1.5L, what is the new temperature
A. 200 K
B. 555.6 K
C. 312.5 K
D. 187.5 K

At 275 K and 3.75 atm pressure, a fixed quantity of gas occupies a volume of 1.25 L. Use the combined gas law (P1V1/T1 = P2V2/T2) to answer the following questions.

What temperature would the gas be at 4.0 L and 0.75 atm?
A. 176 K
B. 4,400 K
C. 275 K
D. 430 K

fixed quantity of gas at a constant pressure has an initial volume of 4.0 L and an initial Temperature of 300K. If I decrease the temperature of the gas and keep the pressure and amount constant, what happens to the volume?
A. increases
B. decreases
C. stays the same

Answer 1

i would help but is hard

Step-by-step explanation:

Answer 2

If the volume of a gas is decreased while keeping the temperature and amount constant, the pressure will increase. The answer is A. Increases.
Using the equation V1/T1 = V2/T2, we have (5.00 L)/(150.0 K) = (10 L)/T2, which can be rearranged to solve for T2: T2 = (10 L)(150.0 K)/(5.00 L) = 300 K. The answer is D. 300 K.
Using the equation P1V1 = P2V2, we have (6 atm)(10.7 L) = (12 atm)V2, which can be rearranged to solve for V2: V2 = (6 atm)(10.7 L)/(12 atm) = 5.35 L. The answer is A. 5.35 L.
The appropriate equation for this problem is P1V1 = P2V2. The answer is D. P1V1 = P2V2.
Using the equation P1V1 = P2V2, we have (6 atm)(10.7 L) = P2(15 L), which can be rearranged to solve for P2: P2 = (6 atm)(10.7 L)/(15 L) = 4.28 atm. The answer is A. 4.28 atm.
Using the combined gas law, we can solve for the new temperature: (3.0 atm)(2.0 L)/(250 K) = (5.0 atm)(1.5 L)/T2. Rearranging to solve for T2 gives T2 = (5.0 atm)(1.5 L)(250 K)/(3.0 atm)(2.0 L) = 312.5 K. The answer is C. 312.5 K.
Using the combined gas law, we can solve for the new temperature: (3.75 atm)(1.25 L)/(275 K) = (0.75 atm)(4.0 L)/T2. Rearranging to solve for T2 gives T2 = (0.75 atm)(4.0 L)(275 K)/(3.75 atm)(1.25 L) = 176 K. The answer is A. 176 K.
If the temperature of a gas is decreased while keeping the pressure and amount constant, the volume will decrease. The answer is B. Decreases.