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Calculate the mole fraction of each component in a solution of 42 g CH3OH, 35 g of chloroform CHCl3, and 50 g C3H7OH. Show your work.

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To calculate the mole fraction of each component in a solution, we need to first calculate the moles of each component and the total moles of the solution.

Given the masses of the three components, we can use the molar masses to calculate the number of moles of each:

CH3OH: 42 g / 32.04 g/mol = 1.312 moles
CHCl3: 35 g / 119.38 g/mol = 0.293 moles
C3H7OH: 50 g / 60.1 g/mol = 0.832 moles
The total number of moles of the solution is the sum of the moles of the three components:

1.312 moles + 0.293 moles + 0.832 moles = 2.437 moles

Now we can calculate the mole fraction of each component by dividing the number of moles of each component by the total number of moles:

Mole fraction of CH3OH = 1.312 moles / 2.437 moles = 0.538
Mole fraction of CHCl3 = 0.293 moles / 2.437 moles = 0.120
Mole fraction of C3H7OH = 0.832 moles / 2.437 moles = 0.342
Therefore, the mole fraction of CH3OH is 0.538, the mole fraction of CHCl3 is 0.120, and the mole fraction of C3H7OH is 0.342.
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