We can solve this system of equations using substitution or elimination method.
Method 1: Substitution Method
In this method, we solve one equation for one variable and substitute the expression in the other equation.
From the first equation, we get y = 3x - 10.
Substituting y in the second equation, we get:
3x + 2(3x - 10) = 16
3x + 6x - 20 = 16
9x = 36
x = 4
Substituting x in the first equation, we get:
y = 3(4) - 10
y = 2
Therefore, the solution of the system is (4, 2).
Method 2: Elimination Method
In this method, we multiply one or both equations by a constant such that one variable gets eliminated when we add or subtract the equations.
Multiplying the first equation by 2, we get:
2y = 6x - 20
Subtracting the above equation from the second equation, we get:
3x + 2y - 2y = 16 - (-20)
3x = 36
x = 4
Substituting x in the first equation, we get:
y = 3(4) - 10
y = 2
Therefore, the solution of the system is (4, 2).