The point of intersection of the two lines is (-1,0)
To obtain the point of intersection, we solve the equation of lines simultaneously.
The equation of line A
m = 3 - ( -1)/4- ( -4)
m = 4/8
m = 1/2
y - (-1) = 1/2( x - (-4)
y + 1 = 1/2( x + 4)
y + 1 = 1/2(x) + 2
y = 1/2x + 1
2y = x + 1
The equation of line B
slope = 6-(-2)/2-(-2)
= 8/4
= 2
y - (-2) = 2( x - (-2))
y + 2 = 2x + 4
y = 2x + 2
Solving the equations simultaneously, substitute 2x + 2 for y
2(2x + 2) = x + 1
4x + 4 = x + 1
3x = -3
x = -1
y = 2(-1) + 2
y = -2+2 = 0
Therefore, the point of intersection is ( -1,0)