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Write an equation of the line that passes through a pair of points:

(- 5, - 2), (3, - 1)
a. y = 1 / 8x + 11 / 8
b. y = 1 / 8 x – 11 / 8
c. y = - 1 / 8 x – 11 / 8
d. y = 1 / 8 + 8 / 11

User Rbajales
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1 Answer

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Answer:

C. y = -1/8x – 11/8.

To find the equation of the line, we can use the point-slope formula of y – y1 = m(x – x1), where m is the slope of the line and (x1, y1) is any given point on the line. The slope m can be found by taking the difference between the y-coordinates of the two points and dividing it by the difference between the x-coordinates of the two points. In this case, the slope m is (–1 – (-2)) / (3 – (-5)) = 3 / 8. Thus, substituting 3/8 for m and (-5, -2) for (x1, y1) into the point-slope formula, we get y – (-2) = (3/8)(x – (-5)), which simplifies to y = -1/8x – 11/8.

User Dusan Bajic
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