Question

HURRY PLEASEEEEE

The stem-and-leaf plot displays the distances that a heavy ball was thrown in feet.

--|----------------------------------
2| 0, 1, 4
--|-----------------------------------
3| 1, 2, 6
--|-----------------------------------
4| 1, 3, 7
--|-----------------------------------
5| 1, 1
--|-----------------------------------
6| 5
--|-----------------------------------
Key: 3|2 means 3.2


What is the mean, and what does it tell you in terms of the problem?
A 3.85 feet; The value means that a typical throw of the ball results in 3.85 feet.
B 3.2 feet; The value means the furthest the ball went.
C 5.1 feet; The value means this measurement had the most occurrences.
D 4.62 feet; The value means that a typical throw of the ball results in 4.62 feet.

Answer 1

To find the mean distance that the heavy ball was thrown, we need to find the sum of all the distances and divide by the total number of distances.

The data from the stem-and-leaf plot can be written as:

20, 21, 24, 31, 32, 36, 41, 43, 47, 51, 51, 56

There are a total of 12 distances, so we can calculate the mean as:

(mean) = (sum of distances) / (number of distances)

(mean) = (20 + 21 + 24 + 31 + 32 + 36 + 41 + 43 + 47 + 51 + 51 + 56) / 12

(mean) = 432 / 12

(mean) = 36

Therefore, the mean distance that the heavy ball was thrown is 36 feet.

Option A is incorrect because the calculated mean is 36 feet, not 3.85 feet.

Option B is incorrect because the stem-and-leaf plot does not provide information about the furthest distance that the ball was thrown.

Option C is incorrect because while the value 51 appears twice, it is not the mode of the data (which would require a value to appear more frequently than any other value).

Option D is incorrect because the calculated mean is 36 feet, not 4.62 feet.

The correct answer is A: 3.85 feet; The value means that a typical throw of the ball results in 3.85 feet.

Answer 2

D. 4.62 feet.

-

The value means that a typical throw of the ball results in 4.62 feet. To calculate the mean from a stem-and-leaf plot, we add up all the data points and divide by the total number of points. In this case, that is (0 + 1 + 4 + 1 + 2 + 6 + 1 + 3 + 7 + 1 + 1 + 5) / 12 = 4.62. This mean value tells us that the average distance a heavy ball is thrown is 4.62 feet.