Question

A 10m/s
B 12m/s
C 14m/s
D 19m/s

Answer 1

C

Step-by-step explanation:

Apply the uniform acceleration equation
`v^(2) = u^(2) +2as`

v: Final velocity (When the stone reaches its maximum height)

u: Initial velocity (The velocity of the stone at the instance when it is thrown)

a: Acceleration due to gravity

s: Displacement of the stone

Take
`v=0m/s` since the stone is momentarily at rest when it reaches its maximum height.

Take
`a = -9.81 m/s^2`, the negative sign indicates the stone is decelerating due to gravity.

Take
`s=10m` as stated in the question.

`0^2=u^2+2(-9.81)(10)`

`196.2=u^2`

`u=√(196.2)`

`u=14.00714104m/s`

Therefore, the closest answer is C (
`14m/s`)