181k views
0 votes
A right angled triangle has base ( x + 3) cm and height (x + 8) cm.

Given that its area is 42 cm , calculate the length of the base and height of the triangle.

1 Answer

2 votes

Answer:

The area of a right-angled triangle is given by the formula A = (1/2)bh, where b is the length of the base and h is the length of the height. We are given that the area of the triangle is 42 cm^2, so we can write:

42 = (1/2)(x+3)(x+8)

Simplifying the right-hand side, we get:

84 = (x+3)(x+8)

Expanding the brackets, we get:

84 = x^2 + 11x + 24

Rearranging, we get:

x^2 + 11x - 60 = 0

We can factorize the left-hand side to get:

(x + 15)(x - 4) = 0

So either x + 15 = 0 or x - 4 = 0. Solving for x in each case, we get:

x = -15 or x = 4

Since the lengths of the base and height of the triangle must be positive, we can disregard the solution x = -15. Therefore, the length of the base is:

x + 3 = 4 + 3 = 7 cm

And the length of the height is:

x + 8 = 4 + 8 = 12 cm

So the base of the triangle is 7 cm and the height is 12 cm.

User Rambou
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.