Question

Find (a) PQ to the nearest tenth and (b) the coordinates of the mid Joint of PQ.P(4, - 4), Q(-2,-3)

Answer 1

(a) The value of PQ to the nearest tenth can be determined as,

`\begin{gathered} PQ=\sqrt[]{(4-(-2))^2+(-4-(-3))^2} \\ =\sqrt[]{6^2+(-1)^2} \\ =\sqrt[]{36+1} \\ =\sqrt[]{37} \\ =6.08\approx6.1 \end{gathered}`

(b) The coordinate of the mid point of PQ can be determined as,

`\begin{gathered} (x,y)=(4-2)/(2),(-4-3)/(2) \\ =1,-3.5 \end{gathered}`

Thus, the required coordinate of the mid point of PQ is (1,-3.5).