Question

Five years ago, father's age was 4 times his son's age. Now (2079 BS) the sum of their ages is 45 years then, (a) । Represent the given statements in terms of linear equations. (b)

b)(Find the present age of father.) ।
c)Find the birth year of son.)​

Answer 1

Explanation:

let the father's current age age be x and the son's be y

five years ago, meaning we subtract 5 from their current ages

(x-5)=4(y-5)

a) x-5= 4y-20

x-4y=-20+5

x-4y=-15 -----1

x+y=45. ------2

b) y= 45-x

substitute the value of y into equation 1

x-4(45-x)=-15

x-180+4x= -15

5x= -15+180

5x= 165

x= 33

c) as the father is 33

33+y= 45

y= 12

the son was born 12 years ago, which was 2079-12=2067