Question

How many grams of ethanol, CH3 CH2 OH, can be vaporized at its boiling point at 78.4 °C with 500 KJ thermal energy?

The ΔH°vap of Ethanol is 36.8 KJ/MOL at this temperature.

Answer 1

500 KJ of thermal energy is equivalent to 13.695 moles of ethanol. Therefore, 13.695 moles of ethanol has a mass of 231.5 grams when vaporized at its boiling point (78.4°C) with 500 KJ thermal energy.