Answer:
Explanation: Given: 200.0g NaBr
next, find the molar mass of NaBr on the periodic table,
Na Sodium- 22.990g/mol
Br Bromine-79.904g/mol
Add these together= 102.894g/mol
Next is one-dimensional analysis: 200.0g NaBr and divide it by your total molar mass 102.894 g/mol NaBr=1.943747935
observe sig figs. When using division, you will round to the least amount of sig fig in the problem. In this case, those 3 sig figs will be=
The final answer is = 1.94 moles of NaBr
Hope this helps:)