Question

Write the equation in point slope form and transform it to Slope-intercept form.

Point: (2, 3 ) ; slope = -5

Answer 1

The point-slope form of a linear equation is given as:

y - y1 = m(x - x1)

where (x1, y1) is the given point and m is the slope of the line.

We are given the point (2, 3) and the slope -5. Plugging these values into the point-slope form, we get:

y - 3 = -5(x - 2)

To transform this equation to slope-intercept form (y = mx + b), we need to isolate y on one side of the equation. We can do this by distributing the -5 and then adding 3 to both sides:

y - 3 = -5x + 10

y = -5x + 13

Therefore, the equation in point-slope form is y - 3 = -5(x - 2) and the equation in slope-intercept form is y = -5x + 13.