Question

How do I solve in trigonometry?

Answer 1

Given:-

• A right angled triangle is given to us with hypotenuse= 42 and base= x .
• One of the angles is 64° .

To find:-

• The value of x.

Answer :-

Here we will make use of trigonometric ratios . As we know that,

`\sf \implies \cos\theta =(base)/(hypotenuse) \dots (1)\\`

And here,

• hypotenuse= 42
• base = x
• 
  `\theta = 64^\circ`

So on substituting the respective values in (1) , we have;

`\sf \implies \cos64^\circ =(x)/(42) \\`

And the value of

• cos 64° = 0.438

`\sf \implies 0.438 = (x)/(42) \\`

`\sf \implies x = 42 * 0.438 \\`

`\sf \implies x = 18.396 \\`

`\sf \implies \underline{\underline{ x \approx 18.4 }} \\`

and we are done!