Question

Assume the different groups of couples use a particular method of Kinda selection, and each couple gives birth to one baby this method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5 assume that the group consist of 43 couples

Answer 1

Explanation:

If we assume that each couple in the group gives birth to one baby, and the probability of having a girl is 0.5, then the probability of having a girl for each couple is also 0.5.

Since there are 43 couples in the group, the total number of babies that will be born is 43.

The probability of having at least one girl in a couple is equal to the probability of having a girl in the first baby or having a girl in the second baby or both, which can be expressed using the complement rule as:

P(at least one girl) = 1 - P(no girls)

The probability of having no girls in a couple is the probability of having a boy in the first baby and a boy in the second baby, which is:

P(no girls) = 0.5 x 0.5 = 0.25

So the probability of having at least one girl in a couple is:

P(at least one girl) = 1 - P(no girls) = 1 - 0.25 = 0.75

Therefore, the probability of having at least one girl in each of the 43 couples is:

P(at least one girl for each couple) = (0.75)^43 = approximately 0.00005

This is a very small probability, which means that it is very unlikely that each couple in the group will have at least one girl if the probability of having a girl is 0.5 and the method of Kinda selection has no effect.