Question

What are the three given variables and the unknown in this problem? (Don't solve it, just list variables.) A sprinter starts from rest, and accelerates at 1.87 m/s² over a distance of 14.0 m. What is her final velocity? A) Given: a, x, Vf; V₁ = ? C) Given: a. Vi, x; vf = ? B) Given: a, vi, x; t = ? D) Given: a, t, x; Vf = ?​

Answer 1

v = 7.2 m/s

Step-by-step explanation:

After covering the 14-meter distance, the sprinter's final speed will be 7.2 m/s.

Describe acceleration.

The rate at which velocity changes in relation to time is referred to as acceleration. In mathematics -

a =Δv/Δt

Given is a sprinter who begins at rest and covers a distance of 14 metres at a speed of 1.87 metres per second. This allows us to write:

Initial speed [u] equals zero

The speed [a] is 1.87 m/s2.

Distance [d] = 14 metres.

Assume that v will be the final velocity.

Using the third motion equation -

v² - u² = 2aS

v² = 2aS

v² = 2 x 1.87 x 14

v² = 52.36

v = √52.36

v = 7.2 m/s