Answer:
The line with a slope of -2/5 and passing through (10,-2) can be expressed in point-slope form as:
y - (-2) = (-2/5)(x - 10)
Simplifying this equation gives:
y = (-2/5)x + 2
The line passing through (0,1) and (5,-1) can be expressed in slope-intercept form as:
y - 1 = [-1 - 1]/[5 - 0](x - 0)
Simplifying this equation gives:
y = -0.4x + 1
Since the two lines have different slopes (-2/5 and -0.4), they are not parallel. To determine if they intersect, we can set the two equations equal to each other and solve for x:
(-2/5)x + 2 = -0.4x + 1
0.2x = 1
x = 5
Substituting x = 5 into either equation gives:
y = (-2/5)(5) + 2 = 0
Therefore, the two lines intersect at the point (5,0), and the answer is B) intersecting lines.