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A 30 inch TV has an aspect ratio of 4:3. A TV that is 4 feet wide and 3 feet tall has a diagonal length of 5 ft. How can you use this information to figure out the width of the 30 inch TV? Explain.

User PmbAustin
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Answer:

the width of the 30 inch TV is 4x = 4 inches.

Explanation:

We can use the fact that the aspect ratio of the 30 inch TV is 4:3, which means that the width of the TV is 4x and the height of the TV is 3x, where x is some constant.

Let's use the Pythagorean theorem to relate the width, height, and diagonal of the TV. We know that the diagonal of the TV is the hypotenuse of a right triangle with legs 4 feet and 3 feet. So, we can write:

diagonal^2 = width^2 + height^2

Substituting the values we know, we get:

(5 ft)^2 = (4x)^2 + (3x)^2

Simplifying, we get:

25 ft^2 = 16x^2 + 9x^2

25 ft^2 = 25x^2

x^2 = 1

Since x is a positive value, we can take the positive square root of both sides:

x = 1

Therefore, the width of the 30 inch TV is 4x = 4 inches.

User Gyscos
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