Question

How would you convert to find the grams of aluminum oxide produced when you are given 100. g of aluminum (Al) and 100. g of oxygen (O₂)?

If you are given 100. g of aluminum (Al) and 100. g of oxygen (O₂), how many grams of aluminum oxide is produced?

Answer 1

The equation for this reaction is Al + O2 --> Al2O3. Since the molar ratio of aluminum to oxygen is 1:3, the number of moles of aluminum required to react with 100 g of oxygen is 25 g. Therefore, the amount of aluminum oxide produced is 75 g (25 g of aluminum reacts with 75 g of oxygen to form Al2O3).