Question

PLEASE HELP How many moles of H2 gas are released when 3.85 moles of HCl react with excess aluminum?

2Al + 6HCl → 2AlCl3 + 3H2

SHOW CONVERSION SET UP

Answer 1

When 3.85 moles of HCl react with excess aluminum, the balanced equation is as follows:

2Al + 6HCl → 2AlCl3 + 3H2

To solve for the number of moles of H2 gas released, we can use a conversion factor that multiplies the number of moles of HCl by the coefficient for H2 on the product side (3).

3.85 moles of HCl x (3 moles of H2 / 6 moles of HCl) = 2.9 moles of H2

Therefore, when 3.85 moles of HCl react with excess aluminum, 2.9 moles of H2 gas are released.