Question

100 POINTS - What mass of KCl can be produced if 30.0 grams of Cl2 reacts with excess KBr?

2KBr + Cl2 → 2KCl + Br2

Show work. PLEASE HELP. Stoichiometry. Show conversion set up.

Answer 1

63.1 g

Step-by-step explanation:

First, we need to find the moles of Cl2 using its molar mass:

30.0 g Cl2 * (1 mol Cl2 / 70.90 g Cl2) = 0.422 mol Cl2

From the balanced chemical equation, we know that 1 mol of Cl2 reacts with 2 mol of KCl, so we can set up a proportion to find the moles of KCl produced:

0.422 mol Cl2 * (2 mol KCl / 1 mol Cl2) = 0.844 mol KCl

Finally, we can convert the moles of KCl to grams using its molar mass:

0.844 mol KCl * (74.55 g KCl / 1 mol KCl) = 63.09 g KCl

Therefore, the mass of KCl produced is 63.1 g.