196k views
5 votes
Calculate the mole fraction of each component of the following solutions: c. 24.0 g C₂H₂O and 10.0 g H₂O​

User Desire
by
7.9k points

1 Answer

4 votes

Answer:

The mole fraction of C₂H₂O is 0.4359, and the mole fraction of H₂O is 0.5641.

Step-by-step explanation:

To calculate the mole fraction of each component in the given solution, we need to determine the number of moles of each component present and then use those values to calculate the mole fraction.

The molar mass of C₂H₂O is 56 g/mol (212 g/mol for carbon + 21 g/mol for hydrogen + 16 g/mol for oxygen), and the molar mass of H₂O is 18 g/mol (2*1 g/mol for hydrogen + 16 g/mol for oxygen).

Number of moles of C₂H₂O = 24.0 g / 56 g/mol = 0.4286 mol

Number of moles of H₂O = 10.0 g / 18 g/mol = 0.5556 mol

Total number of moles = 0.4286 mol + 0.5556 mol = 0.9842 mol

Mole fraction of C₂H₂O = (0.4286 mol / 0.9842 mol) = 0.4359

Mole fraction of H₂O = (0.5556 mol / 0.9842 mol) = 0.5641

Therefore, the mole fraction of C₂H₂O is 0.4359, and the mole fraction of H₂O is 0.5641.

User Noam Ban Ishay
by
8.1k points