Answer:
the probability that a student makes more than 7 mistakes on the exam is 0.39.
Explanation:
Let X be the number of mistakes a student makes on the exam. Then, X follows a binomial distribution with n=16 and some unknown probability of success p (i.e., the probability of answering a question correctly).
We know that P(X<5) = 0.47 and P(5<=X<=7) = 0.14. Using the complement rule, we can find P(X>7) as follows:
P(X>7) = 1 - P(X<=7)
= 1 - P(X<5) - P(5<=X<=7)
= 1 - 0.47 - 0.14
= 0.39
Therefore, the probability that a student makes more than 7 mistakes on the exam is 0.39.