Question

Make a Punnett square for the cross between two people, both of whom are heterozygous for earwax form. Begin by noting the genotypes for each parent.

a. What are the possible genotypes of their offspring, and what is the probability for cách?
b. What are the possible phenotypes of their offspring, and what is the probability for each type of phenotype?

Answer 1

I love doing Punnet squares!

So, let me explain.

Heterozygous meaning the trait takes dominancy and shows, one capital letter and one lowercase. Lets call earwax “B”

There is a 50 percent chance of offspring being heterozygous for earwax (Bb), and 25 percent chance of offspring being homozygous dominant (BB) and 25 percent chance of offspring being homozygous recessive (bb). The bb is the only one who would not have the earwax trait, so 25 percent chance the offspring doesn’t have the earwax trait. 75 percent chance it will in some form.

Hope this helps :)

Answer 2

Since I don't have any trait labels (Aa, Bb, etc) I'll use Aa. I'm not aware of the dominant trait, so you'll have to fill that in as well!

- - - - - - - - - - - - - - - - - - - - - - - -

Heterozygous - a hybrid of two traits, dominant and recessive.

- - - - - - - - - - - - - - - - - - - - - - - -

Here's a rough sketch of the Punnett square, and an explanation.

A. The genotypes can be AA, Aa, Aa, or aa.

B. There is a 75% chance of (dominant form) and 25% (recessive form).

- - - - - - - - - - - - - - - - - - - - - - - -

Good luck!

~pinetree :)