To find the molarity of the solution, we first need to calculate the number of moles of LiNO3 present in the solution, using its given mass and molar mass.
The molar mass of LiNO3 can be calculated by adding the atomic masses of lithium (Li), nitrogen (N), and three oxygen (O) atoms:
Molar mass of LiNO3 = 6.94 g/mol (Li) + 14.01 g/mol (N) + 3 x 16.00 g/mol (O) = 68.94 g/mol
Next, we can calculate the number of moles of LiNO3 by dividing its mass by its molar mass:
Number of moles of LiNO3 = 1.66 g / 68.94 g/mol = 0.0241 mol
Finally, we can calculate the molarity of the solution by dividing the number of moles of solute by the volume of the solution in liters:
Molarity = Number of moles / Volume of solution in liters
The volume of the solution is given as 455 mL, which is equivalent to 0.455 L. Therefore, we can calculate the molarity as:
Molarity = 0.0241 mol / 0.455 L = 0.053 mol/L
Therefore, the molarity of the solution is 0.053 mol/L or 0.053 M (molar).