Answer:
The molarity of the NH3 solution is 32.24 M and the molality is 25.1 m.
Step-by-step explanation:
To calculate the molarity and molality of the NH3 solution, we need to first calculate the number of moles of NH3 and the mass of water in the solution.
The number of moles of NH3 can be calculated as follows:
moles of NH3 = mass of NH3 / molar mass of NH3
moles of NH3 = 30.0 g / 17.03 g/mol (molar mass of NH3)
moles of NH3 = 1.76 moles
The mass of water in the solution can be calculated by subtracting the mass of NH3 from the total mass of the solution:
mass of water = total mass of solution - mass of NH3
mass of water = 70.0 g + 30.0 g
mass of water = 100.0 g
The density of the solution is given as 1.83 g/mL, which means that the volume of the solution can be calculated as:
volume of solution = mass of solution / density of solution
volume of solution = 100.0 g / 1.83 g/mL
volume of solution = 54.64 mL
Now we can calculate the molarity of the NH3 solution as follows:
molarity = moles of solute / volume of solution in liters
molarity = 1.76 moles / 0.05464 L
molarity = 32.24 M
Next, we can calculate the molality of the NH3 solution as follows:
molality = moles of solute / mass of solvent in kilograms
molality = 1.76 moles / 0.0700 kg
molality = 25.1 m
Therefore, the molarity of the NH3 solution is 32.24 M and the molality is 25.1 m.