Question

A 8.15 g sample of hydrogen peroxide (H2O2) decomposes to form water and oxygen. The temperature and pressures conditions in the lab were 21.2oC and 761.4 torr, respectively. The oxygen gas is collected over a sample of water at 21.2oC; the vapor pressure of water at that temperature is 18.9 torr. When the water level inside and outside of the tube is equal the volume of gas is recorded as 176.23 mL. a) Write and balance the equation for the decomposition reaction

Answer 1

The balanced decomposition reaction of hydrogen peroxide (H2O2) is 2H2O2 (l) → 2H2O (l) + O2 (g), which shows the breakdown of two molecules of hydrogen peroxide into two molecules of water and one molecule of oxygen gas.

Step-by-step explanation:

The decomposition reaction for hydrogen peroxide (H₂O₂) is as follows:

1. Balanced equation: 2H₂O₂ (l) → 2H₂O (l) + O₂ (g)

This reaction indicates that two molecules of hydrogen peroxide decompose to form two molecules of water and one molecule of oxygen gas.