Answer: Let $a_n$ denote the $n$th term of the sequence. We know that the sum of the first $n$ terms of the sequence is $n(n-1)(n-2)$, so we can set up the following equation:
$$a_1 + a_2 + \cdots + a_n = n(n-1)(n-2)$$
Since we want to find the tenth term of the sequence, we can substitute $n = 10$ into the above equation to get:
$$a_1 + a_2 + \cdots + a_{10} = 10(10-1)(10-2)$$
Simplifying the right-hand side gives:
$$a_1 + a_2 + \cdots + a_{10} = 720$$
We know that the sum of the first nine terms of the sequence is:
$$a_1 + a_2 + \cdots + a_9 = 9(9-1)(9-2) = 504$$
Subtracting this equation from the previous one, we get:
$$a_{10} = (a_1 + a_2 + \cdots + a_{10}) - (a_1 + a_2 + \cdots + a_9) = 720 - 504 = 216$$
Therefore, the tenth term of the sequence is 216.
Explanation: