Question

If I dilute 350 mL of 2.6 M lithium acetate solution to a volume of 800 mL, what will theconcentration of this solution be?

Answer 1

Step 1

A dilution is calculated as:

`\begin{gathered} M1\text{ x V1 = M2 x V2 \lparen1\rparen} \\ M1\text{ = concentration 1; M2 = concentration 2} \\ V1\text{ = volume 1; V2 = volume 2} \end{gathered}`

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Step 2

Information provided of lithium acetate:

M1 = 2.6 M

V1 = 350 mL

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M2 = unknown

V2 = 800 mL

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Step 3

Procedure: from (1)

M1 x V1/V2 = M2

2.6 M x 350 mL/800 mL = M2

1.1 M approx. = M2

Answer: M2 = 1.1 M