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The height of a seat on a Ferris wheel can be modeled as ___

The height of a seat on a Ferris wheel can be modeled as ___-example-1
User Yanqi Ma
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1 Answer

18 votes
18 votes

Solution:

Given that the height is expressed as


\begin{gathered} H(t)=48\sin((\pi)/(20)t+(3\pi)/(2))+54\text{ ---- equation 1} \\ where \\ t\text{ is the time i seconds} \\ H(t)\text{ is tghe height in feet} \end{gathered}

To find the maximum height,

step 1: Take the first derivative.

Thus,


H(t)^(\prime)=(12\pi)/(5)\sin\left((\pi t)/(20)\right)---\text{ equation 2}

step 2: Find the critical point.

At the critical point, H(t)' equals zero.

Thus,


\begin{gathered} (12\pi)/(5)\sin\left((\pi t)/(20)\right)=0 \\ \Rightarrow\sin\left((\pi t)/(20)\right)=0 \\ take\text{ the sine inverse of both sides} \\ \sin^(-1)(\sin\left((\pi t)/(20)\right))=\sin^(-1)(0) \\ (\pi)/(20)t=\pi \\ thus, \\ t=20 \end{gathered}

step 3: Take the second derivative.

Thus, we have


\begin{gathered} H(t)^(\prime)^(\prime)=(3\pi^2\cos\left((\pi t)/(20)\right))/(25) \\ when\text{ t=20,} \\ H(t)^(\prime)^(\prime)=-(3\pi^2)/(25) \end{gathered}

Since H(t)'' is negative, we have a maximum point.

To evaluate the maximum height, we substitute the value of 20 for t into the H(t) function.

Thus, we have


\begin{gathered} H(t)=48\sin((\pi)/(20)t+(3\pi)/(2))+54 \\ t=20 \\ H(20)=48\sin((\pi)/(20)(20)+(3\pi)/(2))+54 \\ =102\text{ feet} \end{gathered}

Hence, the correct option is

The height of a seat on a Ferris wheel can be modeled as ___-example-1
User Dan Bracuk
by
2.9k points