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The vertex form of h(x) = x2 – 14x + 6 is h(x) = (x –
)2 –
.

User KoljaTM
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1 Answer

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Answer: Find the vertex form of h(x) = x2 - 14x + 6?

Solution:

It is given that,

h(x) = x2 - 14x + 6

We know that the vertex form is obtained by completing the square.

So we have to add and subtract a term, which is formed by the squared power of half the coefficient of the linear term:

= x2 - 14x + 6

= x2 - 14x + 6 + (14/2)2 - (14/2)2

= x2 - 14x + 6 + 72 - 72

= x2 - 14x + 72 + 6 - 72

Use the algebraic identity,

(a - b)2 = a2 - 2ab + b2

= (x - 7)2 + 6 - 72

= (x - 7)2 + 6 - 49

= (x - 7)2 - 43

Therefore, the vertex form of h(x) = x2 - 14x + 6 is (x - 7)2 - 43.

Find the vertex form of h(x) = x2 - 14x + 6?

Summary:

The vertex form of h(x) = x2 - 14x + 6 is (x - 7)2 - 43.

Explanation:

User Abaza
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