To solve this problem, we need to find the number of letters in Jar B that are either 'n' or 't', and then divide this number by the total number of letters in Jar B.
The word 'Connecticut' has three 'n's and two 't's, so there are a total of 3+2 = 5 letters that are either 'n' or 't' in Jar B.
Jar B contains 11 letters in total, so the probability of randomly drawing an 'n' or a 't' from Jar B is:
P = (number of letters in Jar B that are 'n' or 't') / (total number of letters in Jar B)
P = 5/11
Therefore, the probability of randomly drawing an 'n' or a 't' from Jar B is 5/11 or approximately 0.45 (rounded to two decimal places).